Conway base 13 function

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Short description: Counterexample to the converse of the intermediate value theorem


The Conway base 13 function is a function created by British mathematician John H. Conway as a counterexample to the converse of the intermediate value theorem. In other words, it is a function that satisfies a particular intermediate-value property—on any interval (ab), the function f takes every value between f(a) and f(b)—but is not continuous.

In 2018, a much simpler function with the property that every open set is mapped onto the full real line was constructed by Aksel Bergfeldt.[1] This function is also nowhere continuous.

Purpose

The Conway base 13 function was created as part of a "produce" activity: in this case, the challenge was to produce a simple-to-understand function which takes on every real value in every interval, that is, it is an everywhere surjective function.[2] It is thus discontinuous at every point.

Sketch of definition

  • Every real number x can be represented in base 13 in a unique canonical way; such representations use the digits 0–9 plus three additional symbols, say {A, B, C}. For example, the number 54349589 has a base-13 representation B34C128.
  • If instead of {A, B, C}, we judiciously choose the symbols {+, −, .}, some numbers in base 13 will have representations that look like well-formed decimals in base 10: for example, the number 54349589 has a base-13 representation of −34.128. Of course, most numbers will not be intelligible in this way; for example, the number 3629265 has the base-13 representation 9+0−−7.
  • Conway's base-13 function takes in a real number x and considers its base-13 representation as a sequence of symbols {0, 1, ..., 9, +, −, .}. If from some position onward, the representation looks like a well-formed decimal number r, then f(x) = r. Otherwise, f(x) = 0. (Well-formed means that it starts with a + or − symbol, contains exactly one decimal-point symbol, and otherwise contains only the digits 0–9). For example, if a number x has the representation 8++2.19+0−−7+3.141592653..., then f(x) = +3.141592653....

Definition

The Conway base-13 function is a function [math]\displaystyle{ f: \Reals \to \Reals }[/math] defined as follows. Write the argument [math]\displaystyle{ x }[/math] value as a tridecimal (a "decimal" in base 13) using 13 symbols as "digits": 0, 1, ..., 9, A, B, C; there should be no trailing C recurring. There may be a leading sign, and somewhere there will be a tridecimal point to separate the integer part from the fractional part; these should both be ignored in the sequel. These "digits" can be thought of as having the values 0 to 12 respectively; Conway originally used the digits "+", "−" and "." instead of A, B, C, and underlined all of the base-13 "digits" to clearly distinguish them from the usual base-10 digits and symbols.

  • If from some point onwards, the tridecimal expansion of [math]\displaystyle{ x }[/math] is of the form [math]\displaystyle{ A x_1 x_2 \dots x_n C y_1 y_2 \dots }[/math] where all the digits [math]\displaystyle{ x_i }[/math] and [math]\displaystyle{ y_j }[/math] are in [math]\displaystyle{ \{0, \dots, 9\}, }[/math] then [math]\displaystyle{ f(x) = x_1 \dots x_n . y_1 y_2 \dots }[/math] in usual base-10 notation.
  • Similarly, if the tridecimal expansion of [math]\displaystyle{ x }[/math] ends with [math]\displaystyle{ B x_1 x_2 \dots x_n C y_1 y_2 \dots, }[/math] then [math]\displaystyle{ f(x) = -x_1 \dots x_n . y_1 y_2 \dots. }[/math]
  • Otherwise, [math]\displaystyle{ f(x) = 0. }[/math]

For example:

  • [math]\displaystyle{ f(\mathrm{12345A3C14.159} \dots_{13}) = f(\mathrm{A3C14.159} \dots_{13}) = 3.14159 \dots, }[/math]
  • [math]\displaystyle{ f(\mathrm{B1C234}_{13}) = -1.234, }[/math]
  • [math]\displaystyle{ f(\mathrm{1C234A567}_{13}) = 0. }[/math]

Properties

  • According to the intermediate-value theorem, every continuous real function [math]\displaystyle{ f }[/math] has the intermediate-value property: on every interval (ab), the function [math]\displaystyle{ f }[/math] passes through every point between [math]\displaystyle{ f(a) }[/math] and [math]\displaystyle{ f(b). }[/math] The Conway base-13 function shows that the converse is false: it satisfies the intermediate-value property, but is not continuous.
  • In fact, the Conway base-13 function satisfies a much stronger intermediate-value property—on every interval (ab), the function [math]\displaystyle{ f }[/math] passes through every real number. As a result, it satisfies a much stronger discontinuity property— it is discontinuous everywhere.
  • From the above follows even more regarding the discontinuity of the function - its graph is dense in [math]\displaystyle{ \mathbb{R}^2 }[/math].
  • To prove that the Conway base-13 function satisfies this stronger intermediate property, let (ab) be an interval, let c be a point in that interval, and let r be any real number. Create a base-13 encoding of r as follows: starting with the base-10 representation of r, replace the decimal point with C and indicate the sign of r by prepending either an A (if r is positive) or a B (if r is negative) to the beginning. By definition of the Conway base-13 function, the resulting string [math]\displaystyle{ \hat{r} }[/math] has the property that [math]\displaystyle{ f(\hat{r}) = r. }[/math] Moreover, any base-13 string that ends in [math]\displaystyle{ \hat{r} }[/math] will have this property. Thus, if we replace the tail end of c with [math]\displaystyle{ \hat{r}, }[/math] the resulting number will have f(c') = r. By introducing this modification sufficiently far along the tridecimal representation of [math]\displaystyle{ c, }[/math] you can ensure that the new number [math]\displaystyle{ c' }[/math] will still lie in the interval [math]\displaystyle{ (a, b). }[/math] This proves that for any number r, in every interval we can find a point [math]\displaystyle{ c' }[/math] such that [math]\displaystyle{ f(c') = r. }[/math]
  • The Conway base-13 function is therefore discontinuous everywhere: a real function that is continuous at x must be locally bounded at x, i.e. it must be bounded on some interval around x. But as shown above, the Conway base-13 function is unbounded on every interval around every point; therefore it is not continuous anywhere.
  • The Conway base-13 function maps almost all the reals in any interval to 0.[3]

See also

References

  1. "Open maps which are not continuous". 2018-09-27. In an answer to the question. https://math.stackexchange.com/questions/75589/open-maps-which-are-not-continuous/2933144#2933144. 
  2. Bernardi, Claudio (February 2016). "Graphs of real functions with pathological behaviors". Soft Computing 11: 5–6. Bibcode2016arXiv160207555B. 
  3. Stein, Noah. "Is Conway's base-13 function measurable?". https://mathoverflow.net/questions/32641/is-conways-base-13-function-measurable.