Extension and contraction of ideals

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In commutative algebra, the extension and contraction of ideals are operations performed on sets of ideals.

Extension of an ideal

Let A and B be two commutative rings with unity, and let f : AB be a (unital) ring homomorphism. If 𝔞 is an ideal in A, then f(𝔞) need not be an ideal in B (e.g. take f to be the inclusion of the ring of integers Z into the field of rationals Q). The extension 𝔞e of 𝔞 in B is defined to be the ideal in B generated by f(𝔞). Explicitly,

𝔞e={yif(xi):xi𝔞,yiB}

Contraction of an ideal

If 𝔟 is an ideal of B, then f1(𝔟) is always an ideal of A, called the contraction 𝔟c of 𝔟 to A.

Properties

Assuming f : AB is a unital ring homomorphism, 𝔞 is an ideal in A, 𝔟 is an ideal in B, then:

  • 𝔟 is prime in B 𝔟c is prime in A.
  • 𝔞ec𝔞
  • 𝔟ce𝔟

It is false, in general, that 𝔞 being prime (or maximal) in A implies that 𝔞e is prime (or maximal) in B. Many classic examples of this stem from algebraic number theory. For example, embedding [i]. In B=[i], the element 2 factors as 2=(1+i)(1i) where (one can show) neither of 1+i,1i are units in B. So (2)e is not prime in B (and therefore not maximal, as well). Indeed, (1±i)2=±2i shows that (1+i)=((1i)(1i)2), (1i)=((1+i)(1+i)2), and therefore (2)e=(1+i)2.

On the other hand, if f is surjective and 𝔞kerf then:

  • 𝔞ec=𝔞 and 𝔟ce=𝔟.
  • 𝔞 is a prime ideal in A 𝔞e is a prime ideal in B.
  • 𝔞 is a maximal ideal in A 𝔞e is a maximal ideal in B.

Extension of prime ideals in number theory

Let K be a field extension of L, and let B and A be the rings of integers of K and L, respectively. Then B is an integral extension of A, and we let f be the inclusion map from A to B. The behaviour of a prime ideal 𝔞=𝔭 of A under extension is one of the central problems of algebraic number theory.

See also

References