Limit point compact

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In mathematics, a topological space [math]\displaystyle{ X }[/math] is said to be limit point compact[1][2] or weakly countably compact[3] if every infinite subset of [math]\displaystyle{ X }[/math] has a limit point in [math]\displaystyle{ X. }[/math] This property generalizes a property of compact spaces. In a metric space, limit point compactness, compactness, and sequential compactness are all equivalent. For general topological spaces, however, these three notions of compactness are not equivalent.

Properties and examples

  • In a topological space, subsets without limit point are exactly those that are closed and discrete in the subspace topology. So a space is limit point compact if and only if all its closed discrete subsets are finite.
  • A space [math]\displaystyle{ X }[/math] is not limit point compact if and only if it has an infinite closed discrete subspace. Since any subset of a closed discrete subset of [math]\displaystyle{ X }[/math] is itself closed in [math]\displaystyle{ X }[/math] and discrete, this is equivalent to require that [math]\displaystyle{ X }[/math] has a countably infinite closed discrete subspace.
  • Some examples of spaces that are not limit point compact: (1) The set [math]\displaystyle{ \Reals }[/math] of all real numbers with its usual topology, since the integers are an infinite set but do not have a limit point in [math]\displaystyle{ \Reals }[/math]; (2) an infinite set with the discrete topology; (3) the countable complement topology on an uncountable set.
  • Every countably compact space (and hence every compact space) is limit point compact.
  • For T1 spaces, limit point compactness is equivalent to countable compactness.
  • An example of limit point compact space that is not countably compact is obtained by "doubling the integers", namely, taking the product [math]\displaystyle{ X = \Z \times Y }[/math] where [math]\displaystyle{ \Z }[/math] is the set of all integers with the discrete topology and [math]\displaystyle{ Y = \{0,1\} }[/math] has the indiscrete topology. The space [math]\displaystyle{ X }[/math] is homeomorphic to the odd-even topology.[4] This space is not T0. It is limit point compact because every nonempty subset has a limit point.
  • An example of T0 space that is limit point compact and not countably compact is [math]\displaystyle{ X = \Reals, }[/math] the set of all real numbers, with the right order topology, i.e., the topology generated by all intervals [math]\displaystyle{ (x, \infty). }[/math][5] The space is limit point compact because given any point [math]\displaystyle{ a \in X, }[/math] every [math]\displaystyle{ x\lt a }[/math] is a limit point of [math]\displaystyle{ \{a\}. }[/math]
  • For metrizable spaces, compactness, countable compactness, limit point compactness, and sequential compactness are all equivalent.
  • Closed subspaces of a limit point compact space are limit point compact.
  • The continuous image of a limit point compact space need not be limit point compact. For example, if [math]\displaystyle{ X = \Z \times Y }[/math] with [math]\displaystyle{ \Z }[/math] discrete and [math]\displaystyle{ Y }[/math] indiscrete as in the example above, the map [math]\displaystyle{ f = \pi_{\Z} }[/math] given by projection onto the first coordinate is continuous, but [math]\displaystyle{ f(X) = \Z }[/math] is not limit point compact.
  • A limit point compact space need not be pseudocompact. An example is given by the same [math]\displaystyle{ X = \Z \times Y }[/math] with [math]\displaystyle{ Y }[/math] indiscrete two-point space and the map [math]\displaystyle{ f = \pi_{\Z}, }[/math] whose image is not bounded in [math]\displaystyle{ \Reals. }[/math]
  • A pseudocompact space need not be limit point compact. An example is given by an uncountable set with the cocountable topology.
  • Every normal pseudocompact space is limit point compact.[6]
    Proof: Suppose [math]\displaystyle{ X }[/math] is a normal space that is not limit point compact. There exists a countably infinite closed discrete subset [math]\displaystyle{ A = \{x_1, x_2, x_3, \ldots\} }[/math] of [math]\displaystyle{ X. }[/math] By the Tietze extension theorem the continuous function [math]\displaystyle{ f }[/math] on [math]\displaystyle{ A }[/math] defined by [math]\displaystyle{ f(x_n) = n }[/math] can be extended to an (unbounded) real-valued continuous function on all of [math]\displaystyle{ X. }[/math] So [math]\displaystyle{ X }[/math] is not pseudocompact.
  • Limit point compact spaces have countable extent.
  • If [math]\displaystyle{ (X, \tau) }[/math] and [math]\displaystyle{ (X, \sigma) }[/math] are topological spaces with [math]\displaystyle{ \sigma }[/math] finer than [math]\displaystyle{ \tau }[/math] and [math]\displaystyle{ (X, \sigma) }[/math]is limit point compact, then so is [math]\displaystyle{ (X, \tau). }[/math]

See also

Notes

  1. The terminology "limit point compact" appears in a topology textbook by James Munkres where he says that historically such spaces had been called just "compact" and what we now call compact spaces were called "bicompact". There was then a shift in terminology with bicompact spaces being called just "compact" and no generally accepted name for the first concept, some calling it "Fréchet compactness", others the "Bolzano-Weierstrass property". He says he invented the term "limit point compact" to have something at least descriptive of the property. Munkres, p. 178-179.
  2. Steen & Seebach, p. 19
  3. Steen & Seebach, p. 19
  4. Steen & Seebach, Example 6
  5. Steen & Seebach, Example 50
  6. Steen & Seebach, p. 20. What they call "normal" is T4 in wikipedia's terminology, but it's essentially the same proof as here.

References