Frobenius determinant theorem

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In mathematics, the Frobenius determinant theorem was a conjecture made in 1896 by the mathematician Richard Dedekind, who wrote a letter to F. G. Frobenius about it (reproduced in (Dedekind 1968), with an English translation in (Curtis 2003)).

If one takes the multiplication table of a finite group G and replaces each entry g with the variable xg, and subsequently takes the determinant, then the determinant factors as a product of n irreducible polynomials, where n is the number of conjugacy classes. Moreover, each polynomial is raised to a power equal to its degree. Frobenius proved this surprising conjecture, and it became known as the Frobenius determinant theorem. His proof of the theorem sparked a new branch of mathematics known as representation theory of finite groups.[1]

Formal statement

Let a finite group G have elements g1,g2,,gn, and let xgi be associated with each element of G. Define the matrix XG with entries aij=xgigj. Then

detXG=j=1rPj(xg1,xg2,,xgn)degPj

where the Pj's are pairwise non-proportional irreducible polynomials and r is the number of conjugacy classes of G.[2]

Examples

If G=/2=gg2=1, the matrix would be

XG=[x1Gxgxgx1G].

The determinant of this matrix is

detXG=(x1Gxg)(x1G+xg).

The number of irreducible polynomial factors is two, which is equal to the number of conjugacy classes of /2.

If G=S3, the symmetric group of order 3, the matrix would be

XG=[xex(12)x(23)x(31)x(123)x(321)x(12)xex(321)x(123)x(31)x(23)x(23)x(123)xex(321)x(12)x(31)x(31)x(321)x(123)xex(23)x(12)x(123)x(23)x(31)x(12)x(321)xex(321)x(31)x(12)x(23)xex(123)].

The determinant of this matrix factors out as

detXG=(σS3xσ)(σS3sign(σ)xσ)(F(xe,x(123),x(321))F(x(12),x(23),x(31)))2

where F(a,b,c)=a2+b2+c2abbcca. The number of irreducible polynomial factors is three, which is equal to the number of conjugacy clsses of S3. The degree-2 polynomial factor has multiplicity 2.[3]

Proof

This proof is based on the one given by Evan Chen, which involves representation theory.[3] It relies on the following lemma.

Lemma — Let Y be an n×n matrix whose entries are independent variables yij. Then detY is an irreducible polynomial.

Let V=(V,ρ)=[G] be the regular representation of group G. Consider the linear map

T=gGxgρ(g),

whose matrix is given by XG. We wish to examine detT.

By Maschke's theorem, [G] is a semisimple algebra, so it is possible to break down V into a direct sum of irreducible representations,

V=i=1rVidimVi

where each Vi is an irreducible representation of V. This lets us write

detT=i=1r(det(T|Vi))dimVi,

where each det(T|Vi) is a polynomial factor of detT.

A result from character theory states that the number of nonisomorphic irreps of regular representation V equals the number of conjugacy classes of G. This explains why the number of polynomial factors is equal to the number of conjugacy classes.

Furthermore, dimVi is both the degree and multiplicity of the polynomial det(T|Vi), which explains why the degree and multiplicity of each polynomial factor are equal.

To complete the proof, we wish to show that polynomials det(T|Vi) are irreducible and not proportional to each other.

Proof of irreducibility: By Jacobson density theorem, for any matrix MMat(Vi), there exists a particular choice of complex numbers for each xgG such that

M=gGxgρi(g)=T|Vi({xg})

This shows that T|Vi, when viewed as a matrix with polynomial entries, must have linearly independent entries. Thus, by letting each of these entries be an independent variable yij, it follows by Lemma above that detT|Vi is an irreducible polynomial.

Proof of non-proportionality: This follows by noticing that we can read off the character χVi from the coefficients of detT|Vi, using the fact that for all gG, the coefficient of xgx1Gk1 in detT|Vi is equal to χVi(g). Since characters are linearly independent to each other, it follows that detT|Vi is not proportional to any other polynomial factor.

References

  1. Etingof 2005, p. 1
  2. Etingof 2005, Theorem 5.4.
  3. 3.0 3.1 Chen, Chapter 22.