Path space fibration

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In algebraic topology, the path space fibration over a pointed space (X,*)[1] is a fibration of the form[2]

ΩX↪PX→χ↦χ(1)X

where

  • PX is the based path space of the pointed space (X,*); that is, PX={f:I→X∣f continuous,f(0)=*} equipped with the compact-open topology.
  • ΩX is the fiber of χ↦χ(1) over the base point of (X,*); thus it is the loop space of (X,*).

The free path space of X, that is, Map⁡(I,X)=XI, consists of all maps from I to X that do not necessarily begin at a base point, and the fibration XI→X given by, say, χ↦χ(1), is called the free path space fibration.

The path space fibration can be understood to be dual to the mapping cone.[clarification needed] The fiber of the based fibration is called the mapping fiber or, equivalently, the homotopy fiber.

Mapping path space

If f:X→Y is any map, then the mapping path space Pf of f is the pullback of the fibration YI→Y,χ↦χ(1) along f. (A mapping path space satisfies the universal property that is dual to that of a mapping cylinder, which is a push-out. Because of this, a mapping path space is also called a mapping cocylinder.[3])

Since a fibration pulls back to a fibration, if Y is based, one has the fibration

Ff↪Pf→pY

where p(x,χ)=χ(0) and Ff is the homotopy fiber, the pullback of the fibration PY⟶χ↦χ(1)Y along f.

Note also f is the composition

X→ϕPf→pY

where the first map ϕ sends x to (x,cf(x)); here cf(x) denotes the constant path with value f(x). Clearly, ϕ is a homotopy equivalence; thus, the above decomposition says that any map is a fibration up to homotopy equivalence.

If f is a fibration to begin with, then the map ϕ:X→Pf is a fiber-homotopy equivalence and, consequently,[4] the fibers of f over the path-component of the base point are homotopy equivalent to the homotopy fiber Ff of f.

Moore's path space

By definition, a path in a space X is a map from the unit interval I to X. Again by definition, the product of two paths α,β such that α(1)=β(0) is the path β⋅α:I→X given by:

(β⋅α)(t)={α(2t)if 0≤t≤1/2β(2t−1)if 1/2≤t≤1.

This product, in general, fails to be associative on the nose: (γ⋅β)⋅α≠γ⋅(β⋅α), as seen directly. One solution to this failure is to pass to homotopy classes: one has [(γ⋅β)⋅α]=[γ⋅(β⋅α)]. Another solution is to work with paths of arbitrary lengths, leading to the notions of Moore's path space and Moore's path space fibration, described below.[5] (A more sophisticated solution is to rethink composition: work with an arbitrary family of compositions; see the introduction of Lurie's paper,[6] leading to the notion of an operad.)

Given a based space (X,*), we let

P′X={f:[0,r]→X∣r≥0,f(0)=*}.

An element f of this set has a unique extension f~ to the interval [0,∞) such that f~(t)=f(r),t≥r. Thus, the set can be identified as a subspace of Map⁡([0,∞),X). The resulting space is called the Moore path space of X, after John Coleman Moore, who introduced the concept. Then, just as before, there is a fibration, Moore's path space fibration:

Ω′X↪P′X→pX

where p sends each f:[0,r]→X to f(r) and Ω′X=p−1(*) is the fiber. It turns out that ΩX and Ω′X are homotopy equivalent.

Now, we define the product map

μ:P′X×Ω′X→P′X

by: for f:[0,r]→X and g:[0,s]→X,

μ(g,f)(t)={f(t)if 0≤t≤rg(t−r)if r≤t≤s+r.

This product is manifestly associative. In particular, with μ restricted to Ω'X × Ω'X, we have that Ω'X is a topological monoid (in the category of all spaces). Moreover, this monoid Ω'X acts on P'X through the original μ. In fact, p:P′X→X is an Ω'X-fibration.[7]

Notes

  1. ↑ Throughout the article, spaces are objects of the category of "reasonable" spaces; e.g., the category of compactly generated weak Hausdorff spaces.
  2. ↑ Davis & Kirk 2001, Theorem 6.15. 2.
  3. ↑ Davis & Kirk 2001, § 6.8.
  4. ↑ using the change of fiber
  5. ↑ Whitehead 1978, Ch. III, § 2.
  6. ↑ Lurie, Jacob (October 30, 2009). "Derived Algebraic Geometry VI: E[k-Algebras"]. http://www.math.harvard.edu/~lurie/papers/DAG-VI.pdf. 
  7. ↑ Let G = Ω'X and P = P'X. That G preserves the fibers is clear. To see, for each γ in P, the map G→p−1(p(γ)),g↦γg is a weak equivalence, we can use the following lemma:

    Lemma — Let p: D → B, q: E → B be fibrations over an unbased space B, f: D → E a map over B. If B is path-connected, then the following are equivalent:

    • f is a weak equivalence.
    • f:p−1(b)→q−1(b) is a weak equivalence for some b in B.
    • f:p−1(b)→q−1(b) is a weak equivalence for every b in B.

    We apply the lemma with B=I,D=I×G,E=I×XP,f(t,g)=(t,α(t)g) where α is a path in P and I → X is t → the end-point of α(t). Since p−1(p(γ))=G if γ is the constant path, the claim follows from the lemma. (In a nutshell, the lemma follows from the long exact homotopy sequence and the five lemma.)

References