Physics:Semileptonic decay
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Short description: Hadron decay process into both leptons and hadrons
In particle physics the semileptonic decay of a hadron is a decay caused by the weak force in which one lepton (and the corresponding neutrino) is produced in addition to one or more hadrons.[1] An example for this can be
- K0 → e− + νe + π+
This is to be contrasted with purely hadronic decays, such as K0 → π+ + π−, which are also mediated by the weak force.[2]
Semileptonic decays of neutral kaons have been used to study kaon oscillations.[3]
See also
References
- ↑ "Semileptonic decays and indirect probes of new physics" (in en-GB). https://www.imperial.ac.uk/a-z-research/high-energy-physics/research/experiments/lhcb/semileptonic-decays-and-indirect-probes-of-new-physics/.
- ↑ Griffiths, D. J. (1987). Introduction to Elementary Particle. John Wiley & Sons. ISBN 0-471-60386-4.
- ↑ Aoki, S.; Aoki, Y.; Bečirević, D.; Blum, T.; Colangelo, G.; Collins, S.; Della Morte, M.; Dimopoulos, P. et al. (2020-02-11). "FLAG Review 2019" (in en). The European Physical Journal C 80 (2): 113. doi:10.1140/epjc/s10052-019-7354-7. ISSN 1434-6052.
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