Sine-triple-angle circle

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Sine-Triple-Angle Circle

In triangle geometry, the sine-triple-angle circle is one of a circle of the triangle.[1][2] Let A1 and A2 points on BC , a side of triangle ABC . And, define B1, B2, C1 and C2 similarly for CA and AB. If

A=AB1C1=AC2B2,

B=BC1A1=BA2C2,

and

C=CA1B1=CB2A2,

then A1, A2, B1, B2, C1 and C2 lie on a circle called the sine-triple-angle circle.[3] At first, Tucker and Neuberg called the circle "cercle triplicateur".[4]

Properties

  • |A1A2|:|B1B2|:|C1C2|=sin3A:sin3B:sin3C.[5] This property is the reason why the circle called "sine-triple-angle circle". But, the number of circle which cuts three sides of triangle that satisfies the ratio are countless. The centers of these circles are on the hyperbola through the incenter, three excenters, and X(49) (see below for X49).[6]
  • The homothetic centers of Nine-point circle and the circle are the Kosnita point and the focus of Kiepert parabola.
  • The homothetic centers of circumcircle and the circle are X(184), the inverse of Jerabek center in Brocard circle, and X(1147).[7]
  • Intersections of Polar of A,B and C with the circle and BC,CA and AB are colinear.[8]
  • The radius of sine-triple-angle circle is

R|1+8cos(A)cos(B)cos(C)|,

where R is the circumradius of triangle ABC.

Center

The center of sine-triple-angle circle is a triangle center designated as X(49) in Encyclopedia of Triangle Centers.[7][9] The trilinear coordinates of X(49) is

cos(3A):cos(3B):cos(3C).

Generalization

For natural number n>0, if

A1C1A2=(2n1)A(n1)π,

B1A1B2=(2n1)B(n1)π,

and

C1B1C2=(2n1)C(n1)π,

then A1, A2, B1, B2, C1 and C2 are concyclic.[8] Sine-triple-angle circle is the special case in n=2.

Also,

|A1A2|:|B1B2|:|C1C2|=sin(2n1)A:sin(2n1)B:sin(2n1)C.

See also

References

  • V. Thebault (1965). Sine-triple-angle-circle. 65. Mathesis. pp. 282–284. 
  • Ehrmann, Jean-Pierre; Lamoen, Floor van (2002). The Stammler Circles. Forum Geometricorum. pp. 151–161.