Univalent function

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Short description: Mathematical concept

In mathematics, in the branch of complex analysis, a holomorphic function on an open subset of the complex plane is called univalent if it is injective.[1][2]

Examples

The function f:z↦2z+z2 is univalent in the open unit disc, as f(z)=f(w) implies that f(z)−f(w)=(z−w)(z+w+2)=0. As the second factor is non-zero in the open unit disc, z=w so f is injective.

Basic properties

One can prove that if G and Ω are two open connected sets in the complex plane, and

f:G→Ω

is a univalent function such that f(G)=Ω (that is, f is surjective), then the derivative of f is never zero, f is invertible, and its inverse f−1 is also holomorphic. More, one has by the chain rule

(f−1)′(f(z))=1f′(z)

for all z in G.

Comparison with real functions

For real analytic functions, unlike for complex analytic (that is, holomorphic) functions, these statements fail to hold. For example, consider the function

f:(−1,1)→(−1,1)

given by f(x)=x3. This function is clearly injective, but its derivative is 0 at x=0, and its inverse is not analytic, or even differentiable, on the whole interval (−1,1). Consequently, if we enlarge the domain to an open subset G of the complex plane, it must fail to be injective; and this is the case, since (for example) f(εω)=f(ε) (where ω is a primitive cube root of unity and ε is a positive real number smaller than the radius of G as a neighbourhood of 0).

See also

Note

  1. ↑ (Conway 1995)
  2. ↑ (Nehari 1975)

References

This article incorporates material from univalent analytic function on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License.

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