Physics:Hamiltonian vector field

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In mathematics and physics, a Hamiltonian vector field on a symplectic manifold is a vector field defined for any energy function or Hamiltonian. Named after the physicist and mathematician Sir William Rowan Hamilton, a Hamiltonian vector field is a geometric manifestation of Hamilton's equations in classical mechanics. The integral curves of a Hamiltonian vector field represent solutions to the equations of motion in the Hamiltonian form. The diffeomorphisms of a symplectic manifold arising from the flow of a Hamiltonian vector field are known as canonical transformations in physics and (Hamiltonian) symplectomorphisms in mathematics.[1] Hamiltonian vector fields can be defined more generally on an arbitrary Poisson manifold. The Lie bracket of two Hamiltonian vector fields corresponding to functions f and g on the manifold is itself a Hamiltonian vector field, with the Hamiltonian given by the Poisson bracket of f and g.

Definition

Suppose that (M, ω) is a symplectic manifold. Since the symplectic form ω is nondegenerate, it sets up a fiberwise-linear isomorphism

[math]\displaystyle{ \omega:TM\to T^*M, }[/math]

between the tangent bundle TM and the cotangent bundle T*M, with the inverse

[math]\displaystyle{ \Omega:T^*M\to TM, \quad \Omega=\omega^{-1}. }[/math]

Therefore, one-forms on a symplectic manifold M may be identified with vector fields and every differentiable function H: MR determines a unique vector field XH, called the Hamiltonian vector field with the Hamiltonian H, by defining for every vector field Y on M,

[math]\displaystyle{ \mathrm{d}H(Y) = \omega(X_H,Y). }[/math]

Note: Some authors define the Hamiltonian vector field with the opposite sign. One has to be mindful of varying conventions in physical and mathematical literature.

Examples

Suppose that M is a 2n-dimensional symplectic manifold. Then locally, one may choose canonical coordinates (q1, ..., qn, p1, ..., pn) on M, in which the symplectic form is expressed as:[2] [math]\displaystyle{ \omega=\sum_i \mathrm{d}q^i \wedge \mathrm{d}p_i, }[/math]

where d denotes the exterior derivative and denotes the exterior product. Then the Hamiltonian vector field with Hamiltonian H takes the form:[1] [math]\displaystyle{ \Chi_H=\left( \frac{\partial H}{\partial p_i}, - \frac{\partial H}{\partial q^i} \right) = \Omega\,\mathrm{d}H, }[/math]

where Ω is a 2n × 2n square matrix

[math]\displaystyle{ \Omega = \begin{bmatrix} 0 & I_n \\ -I_n & 0 \\ \end{bmatrix}, }[/math]

and

[math]\displaystyle{ \mathrm{d}H=\begin{bmatrix} \frac{\partial H}{\partial q^i} \\ \frac{\partial H}{\partial p_i} \end{bmatrix}. }[/math]

The matrix Ω is frequently denoted with J.

Suppose that M = R2n is the 2n-dimensional symplectic vector space with (global) canonical coordinates.

  • If [math]\displaystyle{ H = p_i }[/math] then [math]\displaystyle{ X_H=\partial/\partial q^i; }[/math]
  • if [math]\displaystyle{ H = q_i }[/math] then [math]\displaystyle{ X_H=-\partial/\partial p^i; }[/math]
  • if [math]\displaystyle{ H=1/2\sum (p_i)^2 }[/math] then [math]\displaystyle{ X_H=\sum p_i\partial/\partial q^i; }[/math]
  • if [math]\displaystyle{ H=1/2\sum a_{ij} q^i q^j, a_{ij}=a_{ji} }[/math] then [math]\displaystyle{ X_H=-\sum a_{ij} q_i\partial/\partial p^j. }[/math]

Properties

  • The assignment fXf is linear, so that the sum of two Hamiltonian functions transforms into the sum of the corresponding Hamiltonian vector fields.
  • Suppose that (q1, ..., qn, p1, ..., pn) are canonical coordinates on M (see above). Then a curve γ(t) = (q(t),p(t)) is an integral curve of the Hamiltonian vector field XH if and only if it is a solution of Hamilton's equations:[1] [math]\displaystyle{ \dot{q}^i = \frac {\partial H}{\partial p_i} }[/math]
[math]\displaystyle{ \dot{p}_i = - \frac {\partial H}{\partial q^i}. }[/math]
  • The Hamiltonian H is constant along the integral curves, because [math]\displaystyle{ \langle dH, \dot{\gamma}\rangle = \omega(X_H(\gamma),X_H(\gamma)) = 0 }[/math]. That is, H(γ(t)) is actually independent of t. This property corresponds to the conservation of energy in Hamiltonian mechanics.
  • More generally, if two functions F and H have a zero Poisson bracket (cf. below), then F is constant along the integral curves of H, and similarly, H is constant along the integral curves of F. This fact is the abstract mathematical principle behind Noether's theorem.[nb 1]
  • The symplectic form ω is preserved by the Hamiltonian flow. Equivalently, the Lie derivative [math]\displaystyle{ \mathcal{L}_{X_H} \omega= 0. }[/math]

Poisson bracket

The notion of a Hamiltonian vector field leads to a skew-symmetric bilinear operation on the differentiable functions on a symplectic manifold M, the Poisson bracket, defined by the formula

[math]\displaystyle{ \{f,g\} = \omega(X_g, X_f)= dg(X_f) = \mathcal{L}_{X_f} g }[/math]

where [math]\displaystyle{ \mathcal{L}_X }[/math] denotes the Lie derivative along a vector field X. Moreover, one can check that the following identity holds:[1] [math]\displaystyle{ X_{\{f,g\}}= [X_f,X_g], }[/math]

where the right hand side represents the Lie bracket of the Hamiltonian vector fields with Hamiltonians f and g. As a consequence (a proof at Poisson bracket), the Poisson bracket satisfies the Jacobi identity:[1] [math]\displaystyle{ \{\{f,g\},h\}+\{\{g,h\},f\}+\{\{h,f\},g\}=0, }[/math]

which means that the vector space of differentiable functions on M, endowed with the Poisson bracket, has the structure of a Lie algebra over R, and the assignment fXf is a Lie algebra homomorphism, whose kernel consists of the locally constant functions (constant functions if M is connected).

Remarks

  1. See (Lee 2003) for a very concise statement and proof of Noether's theorem.

Notes

  1. 1.0 1.1 1.2 1.3 1.4 Lee 2003, Chapter 18.
  2. Lee 2003, Chapter 12.

Works cited