q-exponential

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The term q-exponential occurs in two contexts. The q-exponential distribution, based on the Tsallis q-exponential is discussed in elsewhere.

In combinatorial mathematics, a q-exponential is a q-analog of the exponential function, namely the eigenfunction of a q-derivative. There are many q-derivatives, for example, the classical q-derivative, the Askey–Wilson operator, etc. Therefore, unlike the classical exponentials, q-exponentials are not unique. For example, eq(z) is the q-exponential corresponding to the classical q-derivative while ℰq(z) are eigenfunctions of the Askey–Wilson operators.

The q-exponential is also known as the quantum dilogarithm.[1][2]

Definition

The q-exponential eq(z) is defined as

eq(z)=∑n=0∞zn[n]!q=∑n=0∞zn(1−q)n(q;q)n=∑n=0∞zn(1−q)n(1−qn)(1−qn−1)⋯(1−q)

where [n]!q is the q-factorial and

(q;q)n=(1−qn)(1−qn−1)⋯(1−q)

is the q-Pochhammer symbol. That this is the q-analog of the exponential follows from the property

(ddz)qeq(z)=eq(z)

where the derivative on the left is the q-derivative. The above is easily verified by considering the q-derivative of the monomial

(ddz)qzn=zn−11−qn1−q=[n]qzn−1.

Here, [n]q is the q-bracket. For other definitions of the q-exponential function, see (Exton 1983), (Ismail Zhang), and (Cieśliński 2011).

Properties

For real q>1, the function eq(z) is an entire function of z. For q<1, eq(z) is regular in the disk |z|<1/(1−q).

Note the inverse, eq(z)e1/q(−z)=1.

Addition Formula

The analogue of exp⁡(x)exp⁡(y)=exp⁡(x+y) does not hold for real numbers x and y. However, if these are operators satisfying the commutation relation xy=qyx, then eq(x)eq(y)=eq(x+y) holds true.[3]

Relations

For −1<q<1, a function that is closely related is Eq(z). It is a special case of the basic hypergeometric series,

Eq(z)=1ϕ1(00;z)=∑n=0∞q(n2)(−z)n(q;q)n=∏n=0∞(1−qnz)=(z;q)∞.

Clearly,

limq→1Eq(z(1−q))=limq→1∑n=0∞q(n2)(1−q)n(q;q)n(−z)n=e−z.

Relation with Dilogarithm

eq(x) has the following infinite product representation:

eq(x)=(∏k=0∞(1−qk(1−q)x))−1.

On the other hand, log⁡(1−x)=−∑n=1∞xnn holds. When |q|<1,

log⁡eq(x)=−∑k=0∞log⁡(1−qk(1−q)x)=∑k=0∞∑n=1∞(qk(1−q)x)nn=∑n=1∞((1−q)x)n(1−qn)n=11−q∑n=1∞((1−q)x)n[n]qn.

By taking the limit q→1,

limq→1(1−q)log⁡eq(x/(1−q))=Li2(x),

where Li2(x) is the dilogarithm.

References

  1. ↑ Zudilin, Wadim (14 March 2006). "Quantum dilogarithm". https://wain.mi.ras.ru/PS/mpim-mar2006.pdf. 
  2. ↑ Faddeev, L.d.; Kashaev, R.m. (1994-02-20). "Quantum dilogarithm". Modern Physics Letters A 09 (5): 427–434. doi:10.1142/S0217732394000447. ISSN 0217-7323. Bibcode: 1994MPLA....9..427F. https://www.worldscientific.com/doi/abs/10.1142/S0217732394000447. 
  3. ↑ Kac, V.; Cheung, P. (2011). Quantum Calculus. Springer. p. 31. ISBN 978-1461300724.