Riesz sequence

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In mathematics, a sequence of vectors (xn) in a Hilbert space (H,⟨⋅,⋅⟩) is called a Riesz sequence if there exist constants 0<c≤C<∞ such that c∑n=1∞|an|2≤‖∑n=1∞anxn‖2≤C∑n=1∞|an|2, for every finite scalar sequence {an} and hence, for all {an}n=1∞∈ℓ2.[1][2]

A Riesz sequence is called a Riesz basis if span(xn)‾=H. Equivalently, a Riesz basis for H is a family of the form {xn}n=1∞={Uen}n=1∞, where {en}n=1∞ is an orthonormal basis for H and U:H→H is a bounded bijective operator. Subsequently, there exist constants 0<c≤C<∞ such that[3] c‖f‖2≤∑n=1∞|⟨f,xn⟩|2≤C‖f‖2,∀f∈H. Hence, Riesz bases need not be orthonormal, i.e., they are a generalization of orthonormal bases.[4]

Paley-Wiener criterion

Let {en} be an orthonormal basis for a Hilbert space H and let {xn} be "close" to {en} in the sense that

‖∑ai(ei−xi)‖≤λ∑|ai|2

for some constant λ, 0≤λ<1, and arbitrary scalars a1,…,an (n=1,2,3,…) . Then {xn} is a Riesz basis for H.[5][6]

Theorems

If H is a finite-dimensional space, then every basis of H is a Riesz basis.

Let φ be in the Lp space L2(R), let

φn(x)=φ(x−n)

and let φ^ denote the Fourier transform of φ. Define constants c and C with 0<c≤C<+∞. Then the following are equivalent:[7]

1.∀(an)∈ℓ2,  c(∑n|an|2)≤‖∑nanφn‖2≤C(∑n|an|2)
2.c≤∑n|φ^(ω+2πn)|2≤C

The first of the above conditions is the definition for (φn) to form a Riesz basis for the space it spans.

Kadec 1/4 Theorem

The Kadec 1/4 theorem, sometimes called the Kadets 1/4 theorem, provides a specific condition under which a sequence of complex exponentials forms a Riesz basis for the Lp space L2[−π,π]. It is a foundational result in the theory of non-harmonic Fourier series.

Let Λ={λn}n∈ℤ be a sequence of real numbers such that

supn∈ℤ|λn−n|<14

Then the sequence of complex exponentials {eiλnt}n∈ℤ forms a Riesz basis for L2[−π,π].[8]

This theorem demonstrates the stability of the standard orthonormal basis {eint}n∈ℤ (up to normalization) under perturbations of the frequencies n.

The constant 1/4 is sharp; if supn∈ℤ|λn−n|=1/4, the sequence may fail to be a Riesz basis, such as:[9]λn={n−14,n>00,n=0n+14,n<0When Λ={λn}n∈ℤ are allowed to be complex, the theorem holds under the condition supn∈ℤ|λn−n|<log⁡2π. Whether the constant is sharp is an open question.[9]

See also

Notes

  1. ↑ Christensen 2016, pp. 89–92.
  2. ↑ Balazs, Stoeva & Antoine 2010, p. 3.
  3. ↑ Christensen 2016, pp. 86–87.
  4. ↑ Antoine & Balazs 2012.
  5. ↑ Young 2001, p. 35.
  6. ↑ Paley & Wiener 1934, p. 100.
  7. ↑ Hernandez & Weiss 1996, chpt. 2.1 Multiresolution analysis.
  8. ↑ Young 2001, p. 36.
  9. ↑ 9.0 9.1 Young 2001, p. 37.

References

This article incorporates material from Riesz sequence on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License. This article incorporates material from Riesz basis on PlanetMath, which is licensed under the Creative Commons Attribution/Share-Alike License.