Physics:Coulomb constant

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Short description: Proportionality constant in electrodynamics equations


Value of k Units
8.9875517923(14)×109 N·m2/C2
14.3996 eV·Å·e−2
10−7 (N·s2/C2)c2

The Coulomb constant, the electric force constant, or the electrostatic constant (denoted ke, k or K) is a proportionality constant in electrostatics equations. In SI base units it is equal to 8.9875517923(14)×109 kg⋅m3⋅s−4⋅A−2.[1] It was named after the French physicist Charles-Augustin de Coulomb (1736–1806) who introduced Coulomb's law.[2][3]

Value of the constant

The Coulomb constant is the constant of proportionality in Coulomb's law,

[math]\displaystyle{ \mathbf{F} = k_\text{e}\frac{Qq}{r^2}\mathbf{\hat{e}}_r }[/math]

where êr is a unit vector in the r-direction.[4] In SI:

[math]\displaystyle{ k_\text{e} = \frac{1}{4\pi\varepsilon_0}, }[/math]

where [math]\displaystyle{ \varepsilon_0 }[/math] is the vacuum permittivity. This formula can be derived from Gauss' law,

\oiint[math]\displaystyle{ {\scriptstyle S} }[/math] [math]\displaystyle{ \mathbf{E} \cdot {\rm d}\mathbf{A} = \frac{Q}{\varepsilon_0} }[/math]

Taking this integral for a sphere, radius r, centered on a point charge, the electric field points radially outwards and is normal to a differential surface element on the sphere with constant magnitude for all points on the sphere.

\oiint[math]\displaystyle{ {\scriptstyle S} }[/math] [math]\displaystyle{ \mathbf{E} \cdot {\rm d}\mathbf{A} = |\mathbf{E}|\int_{S} dA = |\mathbf{E}| \times 4\pi r^{2} }[/math]

Noting that E = F/q for some test charge q,

[math]\displaystyle{ \begin{align} \mathbf{F} &= \frac{1}{4\pi\varepsilon_0}\frac{Qq}{r^2}\mathbf{\hat{e}}_r = k_\text{e}\frac{Qq}{r^2}\mathbf{\hat{e}}_r \\[8pt] \therefore k_\text{e} &= \frac{1}{4\pi\varepsilon_0} \end{align} }[/math]

Coulomb's law is an inverse-square law, and thereby similar to many other scientific laws ranging from gravitational pull to light attenuation. This law states that a specified physical quantity is inversely proportional to the square of the distance.[math]\displaystyle{ \text{intensity} = \frac{1}{d^2} }[/math]In some modern systems of units, the Coulomb constant ke has an exact numeric value; in Gaussian units ke = 1, in Heaviside–Lorentz units (also called rationalized) ke = 1/. This was previously true in SI when the vacuum permeability was defined as μ0 = 4π×107 H⋅m−1. Together with the speed of light in vacuum c, defined as 299792458 m/s, the vacuum permittivity ε0 can be written as 1/μ0c2, which gave an exact value of[5]

[math]\displaystyle{ \begin{align} k_\text{e} = \frac{1}{4\pi\varepsilon_0}=\frac{c^2\mu_0}{4\pi}&=c^2\times (10^{-7}\ \mathrm{H{\cdot}m}^{-1})\\ &= 8.987\ 551\ 787\ 368\ 1764\times 10^9~\mathrm{N{\cdot}m^2{\cdot}C^{-2}}. \end{align} }[/math]

Since the redefinition of SI base units,[6][7] the Coulomb constant is no longer exactly defined and is subject to the measurement error in the fine structure constant, as calculated from CODATA 2018 recommended values being[1]

[math]\displaystyle{ k_\text{e} = 8.987\,551\,7923\,(14)\times 10^9\;\mathrm{kg{\cdot}m^{3}{\cdot}s^{-4}{\cdot}A^{-2}} . }[/math]

Use

The Coulomb constant is used in many electric equations, although it is sometimes expressed as the following product of the vacuum permittivity constant:

[math]\displaystyle{ k_\text{e} = \frac{1}{4 \pi \varepsilon_0}. }[/math]

The Coulomb constant appears in many expressions including the following:

Coulomb's law
[math]\displaystyle{ \mathbf{F}=k_\text{e}{Qq\over r^2}\mathbf{\hat{e}}_r. }[/math]
Electric potential energy
[math]\displaystyle{ U_\text{E}(r) = k_\text{e}\frac{Qq}{r}. }[/math]
Electric field
[math]\displaystyle{ \mathbf{E} = k_\text{e} \sum_{i=1}^N \frac{Q_i}{r_i^2} \mathbf{\hat{r}}_i. }[/math]

See also

References